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Dear all,<br>
<br>
a follow-up question to this. Is such a unification or intersection
possible in CQPweb (e.g. with saved queries) or is this planned?<br>
<br>
Best<br>
Hannah<br>
<br>
<div class="moz-cite-prefix">Am 14.12.2015 um 13:58 schrieb Hannah
Kermes:<br>
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<blockquote cite="mid:566EBD07.7010000@mx.uni-saarland.de"
type="cite">
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Hi Alex,<br>
<br>
if this hasn't changed in the newest version, you can combine
named queries in the following way:<br>
A = intersection B C; A = B ∩ C<br>
A = union B C; A = B ∪ C<br>
A = difference B C; A = B \ C<br>
<br>
Best<br>
Hannah<br>
<br>
<div class="moz-cite-prefix">Am 14.12.2015 um 13:35 schrieb
Yannick Versley:<br>
</div>
<blockquote
cite="mid:CAHXjEOYCutaPWQFdVeCSS9TW2sveau8xhvHCk48dR1HH_iVx_A@mail.gmail.com"
type="cite">
<div dir="ltr">Hi Alex,
<div><br>
</div>
<div>if you want to do that with the current CQP, the method
I'd use (short of using the API)</div>
<div>would be to dump A, B and C to files (CQP writes a list
of starting/ending offsets)</div>
<div>and then concatenate/sort these files and read them back
in.</div>
<div>as in</div>
<div>A=[pos='JJ'][pos='NN']</div>
<div>Dump A > 'a.txt'</div>
<div>B=[pos='MD'][pos='VV']</div>
<div>Dump B > 'b.txt'</div>
<div>cat a.txt b.txt | sort > ab.txt</div>
<div>Undump D < 'ab.txt'</div>
<div><br>
</div>
<div>Best,</div>
<div>Yannick</div>
</div>
<div class="gmail_extra"><br>
<div class="gmail_quote">On Mon, Dec 14, 2015 at 12:30 PM,
Trklja, Alex <span dir="ltr"><<a moz-do-not-send="true"
href="mailto:A.Trklja@exeter.ac.uk" target="_blank">A.Trklja@exeter.ac.uk</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">Dear
all,<br>
<br>
Is it possible in CQP to assign cqp queries to new
variables and then re-use them or have you thought about
including something along this line to Ziggurat/CWB4? Say,
I have the following queries:<br>
<br>
A= [pos='JJ'] [pos='NN']<br>
B= [pos='MD] [pos='VV']<br>
C=[pos='RB'] [pos='VV']<br>
<br>
And I would like to combine them in the following two
ways:<br>
D=A+B<br>
E=A+C<br>
<br>
Thanks.<br>
Alex<br>
<br>
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